4.905x^2-24x=88

Solution for 4.905x^2-24x=88 equation:

4.905x^2-24x=88

We move all terms to the left:

4.905x^2-24x-(88)=0

a = 4.905; b = -24; c = -88;
Δ = b2-4ac
Δ = -242-4·4.905·(-88)
Δ = 2302.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-\sqrt{2302.56}}{2*4.905}=\frac{24-\sqrt{2302.56}}{9.81}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+\sqrt{2302.56}}{2*4.905}=\frac{24+\sqrt{2302.56}}{9.81}
$